URI Online Judge 1010 | (Simple Calculate) Solution

Solve of URI 1010 (Simple Calculate) in C & C++

Problem Description of URI Online Judge 1010:

Problem number: 1010.

Problem name: Simple Calculate.

Problem level: 3.

Problem category: Beginner.

Points: 3.1 points

Base time limit: 1 second.

Memory limit: 200 MB.

Problem subject: Sequential.

Problem adapted by: Neilor Tonin (Brazil).

Link: https://www.urionlinejudge.com.br/judge/en/problems/view/1010

Solution language: C & C++

My profile: https://www.urionlinejudge.com.br/judge/en/profile/38770

Solution in C:

//URI online judge 1010 solution in C
//This solution is made by Mehedi Hasan Kajol

#include<stdio.h>
int main(void){
    int code1, quantity1, code2, quantity2;
    double price1, price2, result1, result2, result;
    scanf(" %d %d %lf", &code1, &quantity1, &price1);
    scanf(" %d %d %lf", &code2, &quantity2, &price2);
    result1 = (double)quantity1 * price1; //Type cast int to double
    result2 = (double)quantity2 * price2; //Type cast int to double
    result = result1 + result2; //Adding two product prices.
    printf("VALOR A PAGAR: R$ %.2lf\n",result);
    return 0;
}

Solution in C++:

//URI online judge 1010 solution in C++
//This solution is made by Mehedi Hasan Kajol

#include<iostream>
using namespace std;
int main(void){
    int code1, quantity1, code2, quantity2;
    double price1, price2, result1, result2, result;    
    cin>> code1>> quantity1>> price1;
    cin>> code2>> quantity2>> price2;
    result1 = (double)quantity1 * price1; //Type cast int to double
    result2 = (double)quantity2 * price2; //Type cast int to double
    result = result1 + result2; //Adding two product prices.
    printf("VALOR A PAGAR: R$ %.2lf\n",result); //printf() for precision.
    return 0;
}